Dr. Richard J Stevenson MD Surgeon

Dr. Richard Stevenson is a surgeon in Cincinnati, Ohio. He received his medical degree from University of Cincinnati College of Medicine and has been in practice for 41 years.

Are you Dr. Stevenson? Claim/Edit Profile

Office Location

See Contact Information

Specialty & Clinical Interests

Surgeon: Pediatric

Education & Medical Training

University Hospital/University of Cincinnati College of Medicine
Residency, General Surgery, 1973–1980

Cincinnati Children's Hospital Medical Center
Fellowship, Pediatric Surgery, 1980–1982

University of Cincinnati College of Medicine
Class of 1973

Certifications & Licensure

American Board of Surgery
Certified in Pediatric Surgery

American Board of Surgery
Certified in Surgery

OH State Medical License
Active through 2014

Publications & Presentations

A preliminary investigation of olfactory function in olfactory and auditory-verbal hallucinators with schizophrenia, and normal controls.
Stevenson, R.J., Langdon, R.

Limits to knowing in olfaction.
Stevenson, R.J.

Higher reported saturated fat and refined sugar intake is associated with reduced hippocampal-dependent memory and sensitivity to interoceptive signals.
Francis, H.M., Stevenson, R.J.

See all 84 publications

Report a Correction — If you are aware of information on this page that is out of date or incorrect, please let us know.

Patient Advice & Support


See More
Our Doctor Finder includes most U.S. physicians. Doctors are not ranked, learn more.

Nearby Surgeons

See all Surgeons near Cincinnati, OH See all Surgeons in Ohio

U.S. News Best Hospitals

U.S. News Best Hospitals

To rank the best adult and children's hospitals, U.S. News analyzes data for fewer than 5,000 centers.

See Hospitals by Specialty

Find a Hospital by Location

Your Message Has Been Submitted

As part of our research on the correction you submitted, you may be contacted at the email address provided.

Sorry, Your Message Could Not Be Submitted

Please try again later, or E-mail your message to doctors@usnews.com and include the Web address (URL) of the page that contains incorrect information.